Asked by anonymous

A 500kV power line has a maximum Voltage drop of 3% and is design to carry 1000 Amps. If the conductor has a 0.026 ohms/km resistance, what is the maximum distance the conductor can be run (to the nearest complete km)? Hint: P=IE, E=IR

How do you solve this?

Please help and thank you
Answered by Henry
Rmax = V/I = (500000*.97)/1000=485 Ohms=Max. conductor resistance.

Dmax = 485 Ohms / 0.026Ohms/km=18,654 km.
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