Asked by Vicky

Can someone help me on how to do this problem
2xy(3x^2)(4y^-1)(5z^-3)
Answered by drwls
What is the power of y? Is it 2? Are you supposed to multiply it all out?

It is not clear what the "problem" is. You cannot solve for x, y and z with one equation. In fact, you have not even written an equation.

You have already done a lot of factoring, but 4y^2 -1 and 5z^3 -3 can be factored some more.
Answered by Vicky
well it says to simplify.and that's all it gives me.
its either one of the following answers
a.6x^3/20z^3
b.6x^3y^2/20z^2
c.120x^3/z^3
d.120x^3z^3
Answered by Bobby
its (c), 120x^3/z^3.
Answered by Vicky
thank you.
how did you get the answer?
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