Asked by Joy
Let G be a graph with the vertex set V = {v1, v2, v3, v4, v5}.
If the degrees of the vertices are 5, 1, 0, 6, 2, respectively, does G have an Eulerian path? Why or why not?
If the degrees of the vertices are 5, 1, 0, 6, 2, respectively, does G have an Eulerian path? Why or why not?
Answers
Answered by
MathMate
An Eulerian path is a path which passes through ALL edges exactly once.
This can happen if the graph has either 0 or 2 vertices with odd degrees.
So even an incomplete graph (with degree 0 at one or more vertices) can have an Eulerian path.
This can happen if the graph has either 0 or 2 vertices with odd degrees.
So even an incomplete graph (with degree 0 at one or more vertices) can have an Eulerian path.
Answered by
Joy
MathMate: Is this correct then for the following problem:
Let G be a graph with the vertex set V = [v1, v2, v3, v4, v5). If the degrees of the vertices are 5, 1, 0, 6, 2, respectively, does G have an Eulerian path? Why or why not?
5 + 1 + 0 + 6 + 2 = 14
2E = 14
E = 7
Yes, this problem does have an Eulerian path because it can have an odd degree or an incomplete graph can have the degree of 0 at one or more of the vertices.
Let G be a graph with the vertex set V = [v1, v2, v3, v4, v5). If the degrees of the vertices are 5, 1, 0, 6, 2, respectively, does G have an Eulerian path? Why or why not?
5 + 1 + 0 + 6 + 2 = 14
2E = 14
E = 7
Yes, this problem does have an Eulerian path because it can have an odd degree or an incomplete graph can have the degree of 0 at one or more of the vertices.
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