What mass of hydrochloric acid (in grams) can be neutralized by 2.3g of sodium bicarbonate(Hint: Begin by writing a balanced equation for the reaction between aqueous sodium bicarbonate and aqueous hydrochloric acid.)

Answer 1

NaHCO3 + HCl -> NaCl + CO2 + H2O

n(NaHCO3)=n(HCl)
n(NaHCO3)=m/M=2.3g/83.99*(g/mol)=0.027384 mol

m(HCl)=n*M
m(HCl)=0.027384 mol * 36.46 (g/mol)= 0.9984 g