What mass of hydrochloric acid (in grams) can be neutralized by 2.3g of sodium bicarbonate? (: Begin by writing a balanced equation for the reaction between aqueous sodium bicarbonate and aqueous hydrochloric acid.)

Answer 1

first write the chemical equation:
HCl + NaHCO3 -> NaCl + H2O + CO2
observe that it's already balanced. :)
now we get the molar mass of NaHCO3 (sodium bicarbonate) and HCl (hydrochloric acid),, i expect you already know how to find molar masses.
NaHCO3 : 23 + 1 + 12 + 3*16 = 84 g/mol
HCl = 1 + 35.45 = 36.45 g/mol
*note: i used approximate mass of each element.
solving,
2.3 g NaHCO3 * ( 1 mol NaHCO3 / 84 g NaHCO3 ) * (1 mol HCl / 1 mol NaHCO3) * (36.45 g HCl / 1 mol HCl) = 0.998 g HCl

hope this helps~ :)