Asked by Rosie
In a population with two alleles, B and b, and the allele frequency of b is 0.4. Calculate the allele frequency of heterozygotes if the population is in Hardy–Weinberg equilibrium? Show your work.
Thanks for any help in advance!
Thanks for any help in advance!
Answers
Answered by
Devron
b=0.4
B+b=1, so
1-b=B
B=1-0.4=0.6
(B+b)^2=B^2+2Bb+b^2=1
(0.6)^2+[2(0.4)(0.6)]+(0.4)^2=1
Bb=heterozygous
Bb=2(0.4)(0.6)=0.48
But if you need to know,
BB=0.36
bb=0.16
B+b=1, so
1-b=B
B=1-0.4=0.6
(B+b)^2=B^2+2Bb+b^2=1
(0.6)^2+[2(0.4)(0.6)]+(0.4)^2=1
Bb=heterozygous
Bb=2(0.4)(0.6)=0.48
But if you need to know,
BB=0.36
bb=0.16
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