Asked by Pooja
concentrated aqueous sulphuric acid is 98% sulphuric acid by mass and has a density of 1.80 g/l. Volume of acid required to make one litre of 0.1M sulphuric acid solution is
Answers
Answered by
DrBob222
First you determine the molarity of te H2SO4 (and note that you made a typo). The density of conc H2SO4 is 1.80 g/mL (not 1.80 g/L).
mass H2SO4 in 1L = 1000 mL x 1.80 x 0.98 = ?
Then mols = grams/molar mass and since that's the mols in 1L soln that is the molarity.
For the dilution use the dilution formula which is c1v1 = c2v2 where
c = concn
v = volume.
mass H2SO4 in 1L = 1000 mL x 1.80 x 0.98 = ?
Then mols = grams/molar mass and since that's the mols in 1L soln that is the molarity.
For the dilution use the dilution formula which is c1v1 = c2v2 where
c = concn
v = volume.
Answered by
chemist
Find out the molarity of the solution. Then use M1V1 = M2V2, where M is the molarity.
Answered by
Asem Meiraba
98% by weight means 98 gm H2SO4 in 100 gm solution or 98 g H2SO4 in 2 g water.
Number of moles of H2SO4 = 98/98
= 1
Density = 1.8 g/L
Volume of solution = Mass of solution/ Density
= 100/1.8
= 55.55 ml
= 0.055 L
Applying,
M1V1 = M2V2
18.18 x V1 = 0.1 x1
V1 = 0.0055 L = 5.5 ml
Hence , volume of acid required = 5.5 ml
Number of moles of H2SO4 = 98/98
= 1
Density = 1.8 g/L
Volume of solution = Mass of solution/ Density
= 100/1.8
= 55.55 ml
= 0.055 L
Applying,
M1V1 = M2V2
18.18 x V1 = 0.1 x1
V1 = 0.0055 L = 5.5 ml
Hence , volume of acid required = 5.5 ml
Answered by
Manoti
Yeh 18.18 kahan se aaya
Answered by
Sakshi
The answer is in too detail and further it is not clear. This way of explanation doesn't help students.
Answered by
resham
10M