Question

How much sulphuric acid containing 90% H2SO4 by wt. is needed for the production of 1000 kg of HCl containing 42% HCl by weight in this reaction.

2NaCl + H2SO4 -----> Na2SO4 + 2HCl
mass HCl needed is 1000 kg x 0.42 = 420 kg or 420,000 g HCl, then mols HCl = 420,000/molar mass HCl = ?

Using the coefficients in the balanced equation, convert mols HCl to mols H2SO4.
Then grams H2SO4 (at 100%) = mols H2SO4 x molar mass H2SO4 = ?
Since it is only 90% pure, you will need ?g H2SO4/0.90 = ?
626.484kg
How did you got the answer show full steps!!
No proper answer. Actual answer is 628kg
Calculate the amount of 90% 24H SOrequired for the preparation of 420kg HC

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