Asked by Kritim

How much sulphuric acid containing 90% H2SO4 by wt. is needed for the production of 1000 kg of HCl containing 42% HCl by weight in this reaction.

2NaCl + H2SO4 -----> Na2SO4 + 2HCl
Answered by DrBob222
mass HCl needed is 1000 kg x 0.42 = 420 kg or 420,000 g HCl, then mols HCl = 420,000/molar mass HCl = ?

Using the coefficients in the balanced equation, convert mols HCl to mols H2SO4.
Then grams H2SO4 (at 100%) = mols H2SO4 x molar mass H2SO4 = ?
Since it is only 90% pure, you will need ?g H2SO4/0.90 = ?
Answered by Binayak
626.484kg
Answered by Sanjog
How did you got the answer show full steps!!
Answered by Pooja
No proper answer. Actual answer is 628kg
Answered by Anonymous
Calculate the amount of 90% 24H SOrequired for the preparation of 420kg HC
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