Asked by Joy
If f(x) = log2 (x - 2)3 and g(x) = log8 (x - 2), when is (f + g)(x) = 0?
Answers
Answered by
Steve
working with logs base 2,
since 8=2^3, g(x) = 1/3 log(x-2)
(f+g)(x) = f(x)+g(x)
= 3log(x-2) + 1/3 log(x-2)
= 10/3 log(x-2)
so, if (f+g)(x) = 0,
log(x-2) = 0
x-2 = 1
x = 3
check
log_2(3-2)^3 = 0
log_8(3-2) = 0
since 8=2^3, g(x) = 1/3 log(x-2)
(f+g)(x) = f(x)+g(x)
= 3log(x-2) + 1/3 log(x-2)
= 10/3 log(x-2)
so, if (f+g)(x) = 0,
log(x-2) = 0
x-2 = 1
x = 3
check
log_2(3-2)^3 = 0
log_8(3-2) = 0
Answered by
Joy
Thanks Steve! I am starting to write these down so that way I will understand them. It is easier for me to go off an example. I appreciate all your help.
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