Asked by samuel
A cube of balsa wood (side length = 0.25 m) is tied with a string to the bottom of a waterfilled
container. The wood is completely immersed. What is the tension in the string?
container. The wood is completely immersed. What is the tension in the string?
Answers
Answered by
Elena
T=F(buoyancy) –mg =
= ρ(water)Vg - ρ(balsa)Vg=
=Vg[ρ(water) - ρ(balsa)] =
=0.25³•9.8(1000 – 160)=129 N
= ρ(water)Vg - ρ(balsa)Vg=
=Vg[ρ(water) - ρ(balsa)] =
=0.25³•9.8(1000 – 160)=129 N
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