Asked by Anonymous
Given a triangle with side lengths: root3, root3, 3, find the measure of its smallest angle.
Answers
Answered by
Steve
well,
tan(x/2) = 2/√3
now just take 2*arctan(2/√3)
tan(x/2) = 2/√3
now just take 2*arctan(2/√3)
Answered by
Reiny
Since it is isosceles, we can construct a right-angled triangle with an altitude to the base of 3
then cosØ = 1.5/√3 = 3/2√3
= 3/2√3 * √3/√3
= √3 /2
ahhh, do you recognize the 30-60-90° triangle
(if not, use your calculator)
Ø = 30°
or
then cosØ = 1.5/√3 = 3/2√3
= 3/2√3 * √3/√3
= √3 /2
ahhh, do you recognize the 30-60-90° triangle
(if not, use your calculator)
Ø = 30°
or
Answered by
Steve
Dang. I used x as the vertex angle. Go with Reiny.
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