Question

Two boys and their father are balance on a seesaw. The father, 70kg, sits on one end 0.65m from the center of the seesaw while the two boys sit together on the other end. If each boy weighs 30kg, where should they sit?

Answer 1

Take moments about the centre.

On father's side:
M=70*0.65=45.5 kg-m

On children's side:
M=(30+30)*x

Equate moments and solve for x.

Answer 2

Thanks :)

Answer 3

welllllllllll..................