Asked by Drake
f(x) is a function differentiable at x=1 and f′(1)=1/13. What is the limit of (x^3 - 1)/f(x) - f(1) as x approaches 1?
Answers
Answered by
Steve
using L'Hospital's Rule,
lim = (3x^2-1)/(f'(1)-0) = 3/(1/13) = 39
lim = (3x^2-1)/(f'(1)-0) = 3/(1/13) = 39
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