Question

How many liters of Cl2 has at a pressure of .950 atm and a temperature of 298K will be collected from the reaction of 25 mL of a .100 M aqueous solution of KMnO4 and an excess of HCI?

KMnO4+HCI->MnCl2+Cl2+H2)+KCl
mols KMnO4 = M x L = ?
Use simple stoichiometry to convert mols KMnO4 to mols Cl2, then use PV = nRT and solve for V (in L).

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