Asked by larry
How many liters each of a 55% acid solution and a 80% acid solution must be used to produce 50 liters of a 60% acid solution? (Round to two decimal places if necessary.)
Answers
Answered by
Damon
.55 V1 + .80 V2 = .6(50)
and
V1 + V2 = 50 so V2 = 50 - V1
.55 V1 + .8(50 -V1) = 30 etc
and
V1 + V2 = 50 so V2 = 50 - V1
.55 V1 + .8(50 -V1) = 30 etc
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