Asked by Tiff
Collision derivation problem. A car is released from rest on a frictionless inclined plane. Assume h/L is approximately equal to y/x.
equations.
If the car has a mass of 0.2 kg, the ratio of height to width of the ramp is 11/110, the initial displacement is 2.25 m, and the change in momentum is 0.46 kg*m/s, how far will it coast back up the ramp before changing directions? Use equation :
change in momentum = mass [(2g(h/L)]^(1/2) [(L initial)^(1/2) + (L final)^(1/2)]
I keep plugging everything in and get 0.0196 meters, but that is the wrong answer when I type it in. Any help would be very much appreciated, thank you.
equations.
If the car has a mass of 0.2 kg, the ratio of height to width of the ramp is 11/110, the initial displacement is 2.25 m, and the change in momentum is 0.46 kg*m/s, how far will it coast back up the ramp before changing directions? Use equation :
change in momentum = mass [(2g(h/L)]^(1/2) [(L initial)^(1/2) + (L final)^(1/2)]
I keep plugging everything in and get 0.0196 meters, but that is the wrong answer when I type it in. Any help would be very much appreciated, thank you.