Asked by Tayla

You dissolve 1.05 grams of an unknown diprotic acid in 200.0 mL of H2O. This solution is just neutralized by 5.00 mL of a 1.00 M NaOH solution. What is the molar mass of the unknown acid?
Answered by DrBob222
H2A + 2NaOH ==> 2H2O + Na2A

mols NaOH = M x L = ?
mols H2A = 1/2 that (from the coefficients in the equation).
mols H2A = grams H2A/molar mass H2A. You have grams and mols, solve for molar mass.
Answered by mjohn
420
There are no AI answers yet. The ability to request AI answers is coming soon!