Asked by crystal
if you dissolve 350 g of K(2)CrO(4)in 2.4 kg of water, what is the molality of the solution?
Answers
Answered by
Audre
Molality is found by dividing the moles of solute (K2CrO4) by the Kg of of solvent (H2O).
So first convert g K2CrO4 to moles.
Molecular weight of K2CrO4= 194.19
So 350g/194.19g= 1.8024 moles.
Then 1.8024 moles K2CrO4/ 2.4 kg H2O=
.751 moles/ kg
Hope that helps!
So first convert g K2CrO4 to moles.
Molecular weight of K2CrO4= 194.19
So 350g/194.19g= 1.8024 moles.
Then 1.8024 moles K2CrO4/ 2.4 kg H2O=
.751 moles/ kg
Hope that helps!
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