Question

if you dissolve 350 g of K(2)CrO(4)in 2.4 kg of water, what is the molality of the solution?

Answer 1

Molality is found by dividing the moles of solute (K2CrO4) by the Kg of of solvent (H2O).
So first convert g K2CrO4 to moles.
Molecular weight of K2CrO4= 194.19
So 350g/194.19g= 1.8024 moles.

Then 1.8024 moles K2CrO4/ 2.4 kg H2O=
.751 moles/ kg

Hope that helps!