Since P and Q are x-intercepts, the x of the vertex must lie half-way between them
the x of the vertex is 10
since the vertex also lies on y = -16x
the vertex must be (10, -160)
You can now find the equation of the function,
comparing it to y = ax^2 + bx = c, the values of a, b, and c can be found.
Consider the graph of the quadratic function y=ax^2+bx+c.
If it passes through two points P=(6,0) and Q=(14,0), and its vertex is on the line y=−16x, what is the value of a+b+c?
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May I know how to compare please? What are the steps? Thanks...
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