Question

Which of the following quadratic functions has zeros at x = -3 and x = 2?



y=(x+3)(x-2)
y=(x-3)(x+2)
y=(x+3)^2-2
y=(x-3)^2+2

Answer 1

Y = (x+3)(x-2) = 0.
x+3 = 0. x = -3.

x-2 = 0. x = 2.

So the ans. is a.