Asked by michael
the vapor pressure of water at 45.0 °c is 71.93 mmhg. Calculate the vapor pressure of a solution of 1.50 m Al(NO3)3 at this temperature (assume 100% dissociation)
Answers
Answered by
DrBob222
1.50 m means 1.5 mols AlCl3/kg solvent.
mols in 1 kg solvent = 1000/molar mass H2O = about 55.5 mols.
1.5 mols AlCl3 = 4*1.5 = 6 mols AlCl3 as ions.
Total mols = 6.0 + 55.5 = about 61.5
XH2O = nH2O/total mols
pH2O = XH2O*P<sup>o</sup><sub>H2O
mols in 1 kg solvent = 1000/molar mass H2O = about 55.5 mols.
1.5 mols AlCl3 = 4*1.5 = 6 mols AlCl3 as ions.
Total mols = 6.0 + 55.5 = about 61.5
XH2O = nH2O/total mols
pH2O = XH2O*P<sup>o</sup><sub>H2O
Answered by
ds
no
Answered by
Anonymous
no
Answered by
Fatimah
Please I need the full workings
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