Asked by Amy
At its peak, a tornado is 60.0 m in diameter and carries 500 km/h winds. What is its angular velocity in revolutions per second?
Answers
Answered by
Elena
v=500000/3600 =138.9 m/s
ω=v/R=138.9/30=4.63 rad/s
n= ω/2π=4.63/2 π=0.74 rev/s
ω=v/R=138.9/30=4.63 rad/s
n= ω/2π=4.63/2 π=0.74 rev/s
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