Asked by SIMONAAA
The rate of energy use in a typical house is about 2.0 kW (2.0 × 103
W). If the kinetic
energy of a 1400-kg car is equal to the total energy used by the house in 1 min, what is
the car’s speed?
W). If the kinetic
energy of a 1400-kg car is equal to the total energy used by the house in 1 min, what is
the car’s speed?
Answers
Answered by
Elena
Pt =E =mv²/2
v=sqrt(2Pt/m) =
=sqrt{2•2000•60/1400)=
=13.09 m/s
v=sqrt(2Pt/m) =
=sqrt{2•2000•60/1400)=
=13.09 m/s
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