Asked by Meg
Suppose the solubility of PbCl2 (s) 5.6 x 10^-2 M. Calculate the ksp
Answers
Answered by
DrBob222
........PbCl2 ==> Pb^2+ + 2Cl^-
I......solid......0........0
C......solid......x........2x
E......solid......x........2x
so x = 5.6E-2 and
2x = 2*5.6E-2
Plug those into Ksp expression and solve for Ksp.
Ksp = (5.6E-2)(2*5.6E-2)^2 = ?
I......solid......0........0
C......solid......x........2x
E......solid......x........2x
so x = 5.6E-2 and
2x = 2*5.6E-2
Plug those into Ksp expression and solve for Ksp.
Ksp = (5.6E-2)(2*5.6E-2)^2 = ?