Asked by larry
a crane drops a 1.0 kg steel ball onto a steel plate. the ball's speed just before impact is 2.0 m/s. if the average impact force is 300 N, and the ball is in contact with the plate for 0.01 seconds, what is the bounce back speed right after the impact.
Answers
Answered by
Elena
F=Δp/Δt
FΔt=Δp =p₂-(-p₁)=mv₁+mv₂
(since p₁ directed ↓and p₂ ↑)
v₂ = {FΔt- mv₁}/m =
={300•0.01 - 1•2}/1 = 1 m/s
FΔt=Δp =p₂-(-p₁)=mv₁+mv₂
(since p₁ directed ↓and p₂ ↑)
v₂ = {FΔt- mv₁}/m =
={300•0.01 - 1•2}/1 = 1 m/s
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