Question
A block weighing 6.2 N requires a force of 2.2 N to push it along at constant velocity. What is the cooefficient of friction for the surface? Plsssss help asap..
Answers
MathMate
Frictional resistance = μN
=μmg
=μ6.2N
Force required = 2.2 N
Thus
μ6.2 = 2.2
μ=2.2/6.2 = 0.35 approx.
=μmg
=μ6.2N
Force required = 2.2 N
Thus
μ6.2 = 2.2
μ=2.2/6.2 = 0.35 approx.