Question

A wodden block weighing 200 g is attached to a hanging weighing 45 g with a fine thread . The block is placed on a frictionless surface and after passing thrad over a smooth pulley , hanger is allowed to pull the block . Find the acceleration of the system and tension in the string.

Answer 1

the force on the system is the weight (m*g) of the hanging mass
... a = f / m

the tension in the string is the force necessary to give the block the calculated acceleration
... t = m a

Answer 2

The force pulling the system is .045*9.8 N
That is equal to the acceleration of the system.
a=F/totalmass=.045*9.8/.245 m/s^2
so the tension on the string is the forcepulling on the 200g block...
tension= .200*a=.200*.045*9.8/.245 Newtons

Answer 3

Fffff:ff

Answer 4

Hey friends
The answer is
a= 1.8m/s
T=0.36 N

Answer 5

Total mass=200+45=245
F=mg
F=45×10 = 450N
Acceleration(a) = F/total mass =450/245=1.8m/s^2
Tension(T)=ma =200×1.8=360N