Asked by megan
Two metal alloys, containing 26% copper and 54% copper are to be mixed together to get 210 oz that is 30% copper. How much of each should be used?
Answers
Answered by
MathMate
Ratio required:
(54-30)/(30-26)
=24/4
=6/1
Weight of 26% alloy:210*(6/7)=180 oz
Weight of 54% alloy:210*(1/7)=30 oz
(54-30)/(30-26)
=24/4
=6/1
Weight of 26% alloy:210*(6/7)=180 oz
Weight of 54% alloy:210*(1/7)=30 oz
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