Asked by hello
a craftsperson has 2 alloys of silver. the 1st one is 70%pure silver amd the second one is 50%. how many kilograms of each must be mixed to have 12kg of an alloy which is 65% silver?
Answers
Answered by
Reiny
let the amount of 70% silver be x kg
then the amount of 50% silver must be 12-x kg
.7x + .5(12-x) = .65(12)
70x + 50(12-x) = 65(12)
I am sure you can take it from there.
(I got x=9)
then the amount of 50% silver must be 12-x kg
.7x + .5(12-x) = .65(12)
70x + 50(12-x) = 65(12)
I am sure you can take it from there.
(I got x=9)
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