Asked by Sarah
                can you explain how to find the bond order of (σ1s)^2(σ1s*)^2(σ2s)^2(σ2s*)^2(σ2p)^2(π 2p)^4(π 2p*)^2... I know that Bond order = (number of bonding electrons - number of antibonding electrons)/2 but i have no idea what to do..
            
            
        Answers
                    Answered by
            bonjo
            
    first you need to draw a molecular orbital diagram.  it is with the diagram that can help you identify bonding and antibonding electrons.  
    
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