Question
A gas occupies 560.0 mL at 285 K. To what temperature must the gas be lowered if it is to occupy 250.0 mL? Assume that the pressure remains constant.
Answers
Jai
Assuming the gas is ideal, we use Charles' Law to relate the relationship between Temperature & Volume of gas:
V1/T1 = V2/T2
where:
T1 = initial temperature of gas (in K)
T2 = final temperature of gas (in K)
V1 = initial volume of gas
V2 = final volume of gas
substituting,
(560)/(285) = V2/(250)
V2 = (560*250)/285
V2 = ? (units in mL)
hope this helps~ :)
V1/T1 = V2/T2
where:
T1 = initial temperature of gas (in K)
T2 = final temperature of gas (in K)
V1 = initial volume of gas
V2 = final volume of gas
substituting,
(560)/(285) = V2/(250)
V2 = (560*250)/285
V2 = ? (units in mL)
hope this helps~ :)
Anonymous
127
Chicken
Nothing