Asked by Anonymous
A "rocket car" is launched along a long straight track at t=0s. It moves with constant acceleration a1=3.0m/s^2. At t=2.5s, a second car is launched with constant acceleration a2=9.0m/s^2.
1. At what time does the second car catch up with the first one?
2. How far have the cars traveled when the second passes the first?
1. At what time does the second car catch up with the first one?
2. How far have the cars traveled when the second passes the first?
Answers
Answered by
Steve
1/2 * 3t^2 = 1/2 * 9 (t-2.5)^2
t = 5.9
plug in that value for t into either expression.
t = 5.9
plug in that value for t into either expression.
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