Asked by Bob
A(1,0) is a point on the parabola y=2x(x−1). From point A, point P is moving along the curve towards the origin O(0,0). As P → O, sec^2∠APO → N, where N is a positive integer. What is the value of N?
Answers
Answered by
Steve
Let θ = ∠POA, φ = ∠PAO, β=APO
tanθ = y/x = 2x(x-1)/x = 2(x-1)
So, as P->O, tanθ -> -2
So, cosidering only |tanθ|, we have
θ = arctan(2)
Now, θ+φ+β = π, so since φ->0,
β = π-θ-φ = π - arctan(2)
cosβ -> cos(π - arctan(2)) = 1/√5
so, sec^2 β -> 5
tanθ = y/x = 2x(x-1)/x = 2(x-1)
So, as P->O, tanθ -> -2
So, cosidering only |tanθ|, we have
θ = arctan(2)
Now, θ+φ+β = π, so since φ->0,
β = π-θ-φ = π - arctan(2)
cosβ -> cos(π - arctan(2)) = 1/√5
so, sec^2 β -> 5
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