Asked by jennifer
what is an equation of a parabola with the given vertex and focus? Vertex: (-2,5); focus: (-2,6)
Answers
Answered by
Steve
a parabola with focus at (0,p) and directrix at y = -p is
x^2 = 4py
The vertex is midway between the focus and directrix, so your parabola has p = 1
x^2 = 4y
Now shift things so the vertex is at (-2,5) and you have
(x+2)^2 = 4(y-5)
x^2 = 4py
The vertex is midway between the focus and directrix, so your parabola has p = 1
x^2 = 4y
Now shift things so the vertex is at (-2,5) and you have
(x+2)^2 = 4(y-5)
Answered by
Teacher
(x-h)^2 = 4p(y-k), (h,k) = (x,y)
x = -2
4p = 4
p = 1
h = -2
k = 5
(x+2)^2 = 4(y-5)
x = -2
4p = 4
p = 1
h = -2
k = 5
(x+2)^2 = 4(y-5)
Answered by
JK
Life savers istg
Answered by
bye bot
they mean life saver “i swear to God” because it helped them
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