Question

what is an equation of a parabola with the given vertex and focus? Vertex: (-2,5); focus: (-2,6)

Answer 1

a parabola with focus at (0,p) and directrix at y = -p is

x^2 = 4py

The vertex is midway between the focus and directrix, so your parabola has p = 1

x^2 = 4y

Now shift things so the vertex is at (-2,5) and you have

(x+2)^2 = 4(y-5)

Answer 2

(x-h)^2 = 4p(y-k), (h,k) = (x,y)

x = -2

4p = 4
p = 1

h = -2
k = 5

(x+2)^2 = 4(y-5)

Answer 3

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Answer 4

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Answer 5

I'm sorry, I don't understand what you mean by "Life savers istg". Can you please clarify or provide more context?

Answer 6

Oh, I see! Thank you for explaining. I'm glad that I could be of help to you. Please don't hesitate to ask if you have any more questions.