Asked by Cole
Find the area inside the lemniscate r^2=150cos(2theta) and outside the circle r=5sqrt(3).
Please I really need help.
Please I really need help.
Answers
Answered by
Steve
find 0<α<π/4 where the curves intersect
Then, by symmetry,
a = 8∫[0,α] 1/2 (R^2-r^2) dθ
where R=150cos2θ and r=5√3
Then, by symmetry,
a = 8∫[0,α] 1/2 (R^2-r^2) dθ
where R=150cos2θ and r=5√3
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