Asked by Larry
Find the area inside r=6sintheta and outside r=2+2sintheta
Answers
Answered by
oobleck
a = 2∫[π/6,π/2] 1/2 ((6sinθ)^2-(2+2sinθ)^2) dθ = 4π
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.