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Asked by Larry

Find the area inside r=6sintheta and outside r=2+2sintheta
4 years ago

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Answered by oobleck
a = 2∫[π/6,π/2] 1/2 ((6sinθ)^2-(2+2sinθ)^2) dθ = 4π
4 years ago
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Find the area inside r=6sintheta and outside r=2+2sintheta

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