Asked by ALex
A charge q=+5.11 mC (millicoulombs) has a mass of 0.00456 kg and is accelerated by two rings connected to a voltage source of 1378 volts.
What is the velocity of the charge when it passes through the second ring?
What is the velocity of the charge when it passes through the second ring?
Answers
Answered by
Elena
ℰ=Δφ=1378 V
mv²/2=qΔφ
v=sqrt(2qΔφ/m)=…
mv²/2=qΔφ
v=sqrt(2qΔφ/m)=…
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