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A charge q=+5.11 mC (millicoulombs) has a mass of 0.00456 kg and is accelerated by two rings connected to a voltage source of 1378 volts.

What is the velocity of the charge when it passes through the second ring?

1 answer

ℰ=Δφ=1378 V
mv²/2=qΔφ
v=sqrt(2qΔφ/m)=…

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