Question
1/8(2sin2x-sin4x)= cosxsin^3x prove
Answers
Steve
2sin2x - sin4x
2sin2x - 2sin2x cos2x
2sin2x (1-cos2x)
4sinx cosx (2sin^2 x)
8cosx sin^3(x)
2sin2x - 2sin2x cos2x
2sin2x (1-cos2x)
4sinx cosx (2sin^2 x)
8cosx sin^3(x)