Asked by Riley
1/8(2sin2x-sin4x)= cosxsin^3x prove
Answers
Answered by
Steve
2sin2x - sin4x
2sin2x - 2sin2x cos2x
2sin2x (1-cos2x)
4sinx cosx (2sin^2 x)
8cosx sin^3(x)
2sin2x - 2sin2x cos2x
2sin2x (1-cos2x)
4sinx cosx (2sin^2 x)
8cosx sin^3(x)
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