Question
Solve:
tanx - 2sin2x = 0
0°< or equal to x < 360°
tanx - 2sin2x = 0
0°< or equal to x < 360°
Answers
drwls
x = 0 is one obvious solution.
(sinx/cosx - 2 sin x cosx)= 0
sinx - 2 sinx cos^2x = 0
sinx - 2 sinx(1- sin^2x) = 0
2 sin^2x + sinx = 0
sinx(2 sinx +1) = 0
sinx = 0 or -1/2
x = 0, 180, 210 or 330 degrees
(sinx/cosx - 2 sin x cosx)= 0
sinx - 2 sinx cos^2x = 0
sinx - 2 sinx(1- sin^2x) = 0
2 sin^2x + sinx = 0
sinx(2 sinx +1) = 0
sinx = 0 or -1/2
x = 0, 180, 210 or 330 degrees
CL
how did you get 210 and 330? =S
CL
nevermind, i understand!