Asked by Dennis

Solve in terms of sine and cosine:

sec(x) csc(x)- sec(x) sin(x)



so far I have:
1/cos(x) 1/sin(x) - 1/cos(x) sin(x)

I am not sure where to go to from there. The book says the answer is cot(x) or cos(x)/sin(x)

Thank you in advance.
Answered by drwls
sec(x) csc(x)- sec(x) sin(x)
= (1/cos x)(1/sinx) - sinx/cosx
= [(1/sinx)-sinx]/cos x
= [1 - sin^2x]/(sin x cos x)
= cos^2 x/(sin x cos x)
= cosx/sinx = cot x
Answered by Dennis
Dang, I see where I messed up. Thank you so much.
Answered by Dennis
whoops, sorry everyone. The original message was supposed to be a reply to another post.
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