Asked by Nicole

Solve for y in terms of x . Determine if y is a function of x . If it is, rewrite using notation and determine the domain.


xsquared+12x-3y+9=0

is it
xsquared + 12x +9=3y
f(x)=xsquared + 12x + 6=y ?
Answered by Reiny
no, should be

y = (1/3)x^2 + 4x + 3
(each term had to be divided by 3)

and yes, it is a function whose domain is the set of real numbers
Answered by bobpursley
y=x^2+12x+6

Now, is y a function of x?

What is the domain of x?
Answered by bobpursley
please disregard
Answered by Anonymous
Y=5+-6
y=7+-6X=2
7+=-6=4
y=8-6=8+4=12

SO THE APPLICATION OF X IS ABOUT TO MOVE EXACTLY WERE IT IS AND NEGATIVELY MOVE TO THE POSITIVE NUMBER SO THE ANSWER IS

NEGATIVE 12

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