no, should be
y = (1/3)x^2 + 4x + 3
(each term had to be divided by 3)
and yes, it is a function whose domain is the set of real numbers
Solve for y in terms of x . Determine if y is a function of x . If it is, rewrite using notation and determine the domain.
xsquared+12x-3y+9=0
is it
xsquared + 12x +9=3y
f(x)=xsquared + 12x + 6=y ?
4 answers
y=x^2+12x+6
Now, is y a function of x?
What is the domain of x?
Now, is y a function of x?
What is the domain of x?
please disregard
Y=5+-6
y=7+-6X=2
7+=-6=4
y=8-6=8+4=12
SO THE APPLICATION OF X IS ABOUT TO MOVE EXACTLY WERE IT IS AND NEGATIVELY MOVE TO THE POSITIVE NUMBER SO THE ANSWER IS
NEGATIVE 12
y=7+-6X=2
7+=-6=4
y=8-6=8+4=12
SO THE APPLICATION OF X IS ABOUT TO MOVE EXACTLY WERE IT IS AND NEGATIVELY MOVE TO THE POSITIVE NUMBER SO THE ANSWER IS
NEGATIVE 12