acceleration
=(v1-v0)/t
=(34-10)/5.35 m/s²
=4.486 m/s²
A herd of wildebeests led by Roger is charging down the hall on the way to lunch. They start out at 10 m/s and accelerate at a constant rate for 5.35 s to reach 34 m/s by the time they reach the stairs. How quickly did Roger's velocity change?
3 answers
would that be the following equation:
d = 1/2 (Vi + Vf)t
or
Vf^2=Vi^2+ 2ad
d = 1/2 (Vi + Vf)t
or
Vf^2=Vi^2+ 2ad
nope, Lynn, see MathMate's response.