Asked by Anonymous
solve physics question. a train moves 3.6km from rest to rest in 3minutes. the greatest speed is 90km/h, and the acceleration and retardation are uniform. find the distance travelled at full speed.
Answers
Answered by
Steve
It sounds like the acceleration and deceleration are equal in value. So, since
90km/hr = 25m/s
3 min = 180 sec
3.6km = 3600m
If acceleration/deceleration take t seconds, leaving u seconds for full-speed travel,
2t+u = 180
at = 25
at^2 + 25u = 3600
a = 25/3
t = 36
u = 108
so, going 25m/s for 108s = 2700m = 2.7 km
90km/hr = 25m/s
3 min = 180 sec
3.6km = 3600m
If acceleration/deceleration take t seconds, leaving u seconds for full-speed travel,
2t+u = 180
at = 25
at^2 + 25u = 3600
a = 25/3
t = 36
u = 108
so, going 25m/s for 108s = 2700m = 2.7 km
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