Asked by Anonymous

solve physics question. a train moves 3.6km from rest to rest in 3minutes. the greatest speed is 90km/h, and the acceleration and retardation are uniform. find the distance travelled at full speed.

Answers

Answered by Steve
It sounds like the acceleration and deceleration are equal in value. So, since

90km/hr = 25m/s
3 min = 180 sec
3.6km = 3600m

If acceleration/deceleration take t seconds, leaving u seconds for full-speed travel,

2t+u = 180
at = 25
at^2 + 25u = 3600

a = 25/3
t = 36
u = 108

so, going 25m/s for 108s = 2700m = 2.7 km
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