Asked by Crystal

Physics Question Please Help?
A wire, 20.0 m long, moves at 4.0 m/s perpendicularly through a magnetic field. An EMF of 40V is induced in the wire. What is strength of the magnetic field?
Answered by drwls
EMF = B*L*v

L = 20 m
EMF = 40 Volts
v = 4.0 m/s

Solve for B in units of Tesla (T)

For a derivation, see
http://library.thinkquest.org/16600/advanced/inducedemf.shtml
Answered by josh
What happens to a magnetic field if the current carrying wire A has three times as many loops but the same current as the current carrying wire B?
Answered by Maryam
v=EMF/(L)(B) =
=40/(20)(4)=0.5 T
Answered by ش
A 20.0-m-long wire moves perpendicularly through a magnetic field at 4.0 m/s. An EMF of
40 V is induced in the wire. What is the field’s strength?
Answered by ش
At what speed would a 0.20-m length of wire have to move across a 2.5-T magnetic field to
induce an EMF of 10 V?
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