Asked by Anonymousab
how do you solve this can you do this with the steps do I an understand them,please.
3 outside the square root like a cube.
(square root start) 64x^6/27 (square root end)
3 outside the square root like a cube.
(square root start) 64x^6/27 (square root end)
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Answered by
Anonymousab
could someone answer this
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