4x^3 - 6x^2 < 0
2x^2 (2x-3) < 0
You should know the general shape of this graph. It has a double root at x=0 and it crosses the x-axis at x=3/2.
So, the graph is below the x-axis for all values of x less than 3/2, except x=0.
2x-3 < 0 is an inequality.
You cannot change it to an equation: x = 3/2
2x-3 < 0
2x < 3
x < 3/2
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If 2x^2 < 0
you cannot say x^2 < 1/2
0/2 = 0
HINT: x^2 is always >=0, so 2x^2 is always >= 0.
Always
(a) check your answer in the original expression
(b) THINK about your answer in the context of the problem!
Please please help!!!!!
Solve the inequality and write the solution set in interval notation
4x^3 -6x^2<0
2x^2 (2x-3)<0
2x-3<0
x= 3/2
Now I'm not sure about this
2x^2<0
x^2<1/2
sq root of x^2<sq root of 1/2
x=.7071
Right?
When I plug it in the calculator it says
X=0
How?
2 answers
x≤−1 or x≥7
1 answer