Question

The equation of motion of a particle is s=4t^3−7t, where s is in meters and t is in seconds. Find
a) the velocity of the particle as a function of t : v(t)=
b) the acceleration of the particle as a function of t : a(t)=
c) the velocity after 5 seconds
d) the acceleration after 5 seconds

Answer 1

Find a cubic function y=ax3^+bx^2+cx+d whose graph has horizontal tangents at the points (-1, -16) and (1,12).

Answer 2

Don't post a new question as a reply to somebody else's problem. Tutors will think the question has been answered.

Patrick's problem:

v(t) = 12t^2 - 7
a(t) = 24t

c) v(5) = 12(25) - 7 = ...
d) a(5) = .....