Asked by Kyle

A lawnmower tractor engine produces 18hp using 40kW of heat transfer from burning fuel. Find the thermal efficiency and the rate of heat transfer rejected to the ambient.

I converted the power to 13.24kW then found the efficiency by dividing 13.24kW by 40kW but the answer is incorrect?
Answered by Saurabh
Yes I am right there with you. I got 0.33 which is 33%. I think the answer in the textbook is wrong, check with your professor because that is what I am going to do.
There are no AI answers yet. The ability to request AI answers is coming soon!