Ask a New Question

Question

A lawnmower engine with an efficiency of 0.29 rejects 5500 J of heat every second. What is the magnitude of the work that the engine does in one second?
12 years ago

Answers

bobpursley
.29=(input-waste)/input
solving for input..

input(1-.29)=waste
but work=.29 input

work/.29 (.71)=5500

work=.29*5500/.71

check that
12 years ago

Related Questions

if a lawnmower is 45 % off and the sale price is 114.95-what is the original cost? 1.) A lawnmower engine claims to provide 18 hp of power and 6.25 ft lb of torque. If this is true, w... A car's engine is only 12% efficient at converting chemical energy in gasoline into mechanical ener... A 10 kg lawnmower is pushed along by a force applied at a 20* angle to the horizontal. If the mower... A man pulls a lawnmower with a mass of 50 kilogram accross a lawn, its pulling force is 400 newtons... a man pushes a lawnmower of mass 50kg at a constant velocity over a horizontal lawn.he exerts a push... A lawnmower tractor engine produces 18hp using 40kW of heat transfer from burning fuel. Find the the... a 33 kg lawnmower is pulled by a 100N force on flat ground. The handle makes a 10 degree angle with... Your lawnmower uses a gasoline and oil mixture for fuel. For every 2 gallons of gas you add 18 ounce... As the lawnmower approaches Gnomeo and Juliet, they can’t run away. Why not? Group of answer choice...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use