Question
The sum of squares formula is given by
1^2+2^2+3^2+…+n^2=n(n+1)(2n+1)/6.
The sum of odd squares can be expressed as
1^2+3^2+5^2+…+(2n−1)^2=An^3+Bn^2+Cn+D.
The value of A can be expressed as ab, where a and b are positive coprime integers. What is the value of a+b?
1^2+2^2+3^2+…+n^2=n(n+1)(2n+1)/6.
The sum of odd squares can be expressed as
1^2+3^2+5^2+…+(2n−1)^2=An^3+Bn^2+Cn+D.
The value of A can be expressed as ab, where a and b are positive coprime integers. What is the value of a+b?
Answers
ravi&ashu
htat 's easy one